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Tuesday, July 26, 2005

ALEXANDER WILL BE IN CAMP FRIDAY 

Big, big news to report on the Seahawks front.

Running back Shaun Alexander will be in training camp on Friday in Cheney.

Alexander has signed a one-year, $6.32 million contract, so he will be with the Seahawks for at least the 2005 season. This is not the tender, in case you were wondering. However, this is a guaranteed deal. There is a clause in the contract that prohibits the Seahawks from trading Alexander without prior approval. In addition, the Seahawks cannot place the franchise tag on Alexander.

The Seahawks and Alexander can now talk about a long-term deal, which I think will get done. When will it get done? Your guess is as good as mine. But I do trust Shaun when he says he wants to stay in Seattle.

Now I can truly say this has been a great offseason for the Seahawks. Don't let the national media fool you, folks. This really has been a great offseason for the Seahawks. I can go through the big free agent signings (Jamie Sharper, Andre Dyson, Kelly Herndon, Bryce Fisher, Joe Jurevicius, Jerome Pathon, etc.). But in reality, the success of the Seahawks offseason can be summed up like this:

The big three pieces of the Seahawks offense are back for the 2005 season.

Matt Hasselbeck. Walter Jones. Shaun Alexander.

Training camp starts Friday. Yes, Shaun will be there!

(The Pump is below this post, for obvious reasons.)

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